这个二重积分怎么做?

2025-06-20 17:05:55
推荐回答(1个)
回答1:

当0<=y<=1时,f(y)=2;当y<0或y>1时,f(y)=0
当0<=x-y<=1,即x-1<=y<=x时,f(x-y)=2;当yx时,f(x-y)=0
所以,当0<=y<=1且x-1<=y<=x时,f(y)f(x-y)=4;在其他区域,f(y)f(x-y)=0
令D'={(x,y)|0<=y<=1且x-1<=y<=x},平行四边形D'的面积=1
原式=∫∫(D')4dxdy
=4*1
=4