解：如题，y=ln x+1/x-1x€(1,+无穷大)所以函数值域为y>0y=ln x+1/x-1e^y=x+1/x-1=1+(2/x-1)e^y-1=2/(x-1)x-1=2/(e^y-1)x=1+[2/e^y-1)]反函数为y=1+[2/(e^x-1)],(x>0)
