(2sin50°+sin80°(1+根号3tan10°))⼀根号下(1+cos10°)

2025-06-21 15:18:24
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回答1:

要用到和差化积[2sin50+sin80(1+√3tan10)]/√(1+cos10)=(2sin50+cos10(1+根号3*tan10)]/根号[2*(cos5)^2]=(2sin50+cos10+根号3*sin10)/[根号2 * cos5]=(2sin50+2sin(30+10))/[根号2 * cos5]=根号2*(sin50+sin40)/cos5=2根号2 *sin45*cos5/cos5=2