已知sin(a+b)=1⼀2,sin(a-b)=1⼀3, (1)求证:sinasinb=5cosasinb (2)求证:tana=5tanb

2025-06-21 03:01:15
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回答1:

(1)sin(a+b)=1/2,sin(a-b)=1/3,则sinacosb+cosasinb=1/2,sinacosb-cosasinb=1/3,则sinacosb=5/12,cosasinb=1/12,所以sinacosb=5cosasinb(你抄错题了吧)(2)由(1)中将cosb除到右边将cosa除到左边即可得