y=x^2 (1) y=2x (2) (1)=(2) x^2-2x=0 x=0 or 2 A= ∫ (0->2) (y2-y1) dx =∫ (0->2) (2x-x^2) dx = [x^2-(1/3)x^3] |(0->2) =4 - 8/3 = 4/3
