解析 log3 2=a log5 3=b log2 5 =lg2/lg5 =log3 2/log3 5 =ab
log<3>2 =a
lg2/lg3 =a (1)
log<3>5 = b
lg5/lg3 = b (2)
(1)+(2)
(lg2+lg5)/lg3 = a+b
1/lg3 =a+b
lg3 = 1/(a+b)
/
lg√3
=(1/2)lg3
=(1/2) [1/(a+b)]
内容全部来源于网络收集，如有侵权，请联系网站删除：QQ：24596024