有abc三个自然数,a×b=15,a×c=21,b×c=35,a×b×c是多少

2025-06-21 19:53:49
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回答1:

a×b=15,a×c=21,b×c=35
(a×b)*(a×c)*(b×c)
=(a×b×c)^2
=15*21*35
=11 025
所以 a×b×c=105