x2-y2=(x+y)(x-y)=105又105=1×105=3×35=5×21=7×15由于题中要求正整数解,故x+y>x-y∴令x+y=105,x-y=1,解得x=53,y=52.令x+y=35,x-y=3,解得x=19,x-y=16.令x+y=21,x-y=5,解得x=13,y=8.令x+y=15,x-y=7,解得x=11,y=4.故满足题意的正整数解共有4组.故选D.