第四题,第四小节数学题怎么做?求解

2025-06-21 06:17:04
推荐回答(1个)
回答1:

4.
(4)
y'=[(x²-1)³]'+1'
=3(x²-1)²·(x²-1)'+0
=3(x²-1)²·2x
=6x(x²-1)²
y''=6x'·(x²-1)²+6x·[(x²-1)²]'
=6(x²-1)²+6x·2(x²-1)·(x²-1)'
=6(x²-1)²+6x·2(x²-1)·2x
=30x⁴-36x²+6