lim((x,y)→(0,0)) (xy)^2/(x^2+y^2)换元,x=ρcosθ,y=ρsinθ=lim(ρ→0) (ρ^2sinθcosθ)^2/ρ^2=lim ρ^2*(sinθcosθ)^2因为,ρ^2→0,(sinθcosθ)^2有界因此=0有不懂欢迎追问