如图所示的电路中,电阻R 1 =6 Ω,R 2 =12 Ω,已知通过电阻R 1 的电流I 1 =0.5A,求:(1)120s内通过

2025-06-20 12:13:19
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回答1:

(1)120s内通过电阻R 1 的电荷量Q=I 1 t=0.5A×120s=60C.
(2)电源电压U=I 1 R 1 =0.5A×6Ω=3V,
         通过电阻R 2 的电流I 2 = = =0.25A,
         干路电流I=I 1 +I 2 =0.5A+0.25A=0.75A.