解方程:①2(x+2) 2 -8=0②2(x-3) 2 =x(x-3)③2x 2 -4x-1=0

解方程:①2(x+2) 2 -8=0②2(x-3) 2 =x(x-3)③2x 2 -4x-1=0.
2025-06-21 14:46:17
推荐回答(1个)
回答1:

①:除以2得:(x+2) 2 -4=0,
∴(x+2+2)(x+2-2)=0,
即x+4=0,x=0,
∴x 1 =0,x 2 =-4.

②:移项得:2(x-3) 2 -x(x-3)=0,
∴(x-3)(2x-6-x)=0,
即x-3=0,x-6=0,
∴x 1 =3,x 2 =6.

③:由2x 2 -4x-1=0得,
b 2 -4ac=(-4) 2 -4×2×(-1)=24,
∴x=
24
2×2
=
6
2

∴x 1 =
2+
6
2
,x 2 =
2-
6
2