x²-ax+a-1=0如何因式分解

步骤 详细
2025-06-22 04:54:06
推荐回答(2个)
回答1:

x²-ax+a-1=x²-1-a(x-1)=(x+1)(x-1)-a(x-1)=(x-1)(x-a+1)

回答2:

x²-ax+a-1=0
x^2-[(a-1)+1]x+1*(a-1)=0
[x-(a-1)](x-1)=0
(x-a+1)(x-1)=0