tanx 求导数是什么

2025-06-21 14:33:30
推荐回答(1个)
回答1:

(tanx)' = 1/(cosx)^2 = (secx)^2
(tanx)'
= (sinx/cosx)'
= [cosx*cosx - sinx(-sinx)]/(cosx)^2
= 1/(cosx)^2
= (secx)^2