1、对f(x)=6-12x+x^3求导令导数 f'(x)=3x^2-12=0解得x=2 或x=-2从而分3个区间讨论函数单调性x=<-2 f'(x)=3x^2-12>=0 f(x)单调递增-2= x>=-2 f'(x)=3x^2-12>=0 f(x)单调递增2、当x属于【-1/3,1】时 显然f(x)单调递减不等式f(x)f(x)max=f(-1/3)=269/27m>269/27即可
