设Sn是等比数列[an]的前n项和,S3,S9,S6成等差数列,且a2加a5等于2am,求m等于

2025-06-23 07:22:59
推荐回答(1个)
回答1:

S3=a1(1-q^3)/(1-q),S9=a1(1-q^9)/(1-q).S6=a1(1-q^6)/(1-q)
因为S3,S9,S6成等差数列,
则S3+S6=2S9 即q^3+q^6=2*q^9 .
同除以q^3,则2q^6-q^3-1=0 q^3=-1/2
a2+a5=a2(1+q^3)=(1/2)a2=2* q^6*a2
得am=a2* q^6=a8
所以m=8
望采纳